676. Implement Magic Dictionary
¶
Problem
Design a data structure that is initialized with a list of different words. Provided a string, you should determine if you can change exactly one character in this string to match any word in the data structure.
Implement the MagicDictionary class:
MagicDictionary()Initializes the object.void buildDict(String[] dictionary)Sets the data structure with an array of distinct stringsdictionary.bool search(String searchWord)Returnstrueif you can change exactly one character insearchWordto match any string in the data structure, otherwise returnsfalse.
Example 1:
Input
["MagicDictionary", "buildDict", "search", "search", "search", "search"]
[[], [["hello", "leetcode"]], ["hello"], ["hhllo"], ["hell"], ["leetcoded"]]
Output
[null, null, false, true, false, false]
Explanation
MagicDictionary magicDictionary = new MagicDictionary();
magicDictionary.buildDict(["hello", "leetcode"]);
magicDictionary.search("hello"); // return False
magicDictionary.search("hhllo"); // We can change the second 'h' to 'e' to match "hello" so we return True
magicDictionary.search("hell"); // return False
magicDictionary.search("leetcoded"); // return False
Constraints:
1 <= dictionary.length <= 1001 <= dictionary[i].length <= 100dictionary[i]consists of only lower-case English letters.- All the strings in
dictionaryare distinct. 1 <= searchWord.length <= 100searchWordconsists of only lower-case English letters.buildDictwill be called only once beforesearch.- At most
100calls will be made tosearch.