1008. Construct Binary Search Tree from Preorder Traversal ¶
Problem
Given an array of integers preorder, which represents the preorder traversal of a BST (i.e., binary search tree), construct the tree and return its root.
It is guaranteed that there is always possible to find a binary search tree with the given requirements for the given test cases.
A binary search tree is a binary tree where for every node, any descendant of Node.left
has a value strictly less than Node.val
, and any descendant of Node.right
has a value strictly greater than Node.val
.
A preorder traversal of a binary tree displays the value of the node first, then traverses Node.left
, then traverses Node.right
.
Example 1:
Input: preorder = [8,5,1,7,10,12] Output: [8,5,10,1,7,null,12]
Example 2:
Input: preorder = [1,3] Output: [1,null,3]
Constraints:
1 <= preorder.length <= 100
1 <= preorder[i] <= 1000
- All the values of
preorder
are unique.