2074. Reverse Nodes in Even Length Groups¶
Problem
You are given the head
of a linked list.
The nodes in the linked list are sequentially assigned to non-empty groups whose lengths form the sequence of the natural numbers (1, 2, 3, 4, ...
). The length of a group is the number of nodes assigned to it. In other words,
- The
1st
node is assigned to the first group. - The
2nd
and the3rd
nodes are assigned to the second group. - The
4th
,5th
, and6th
nodes are assigned to the third group, and so on.
Note that the length of the last group may be less than or equal to 1 + the length of the second to last group
.
Reverse the nodes in each group with an even length, and return the head
of the modified linked list.
Example 1:
Input: head = [5,2,6,3,9,1,7,3,8,4] Output: [5,6,2,3,9,1,4,8,3,7] Explanation: - The length of the first group is 1, which is odd, hence no reversal occurs. - The length of the second group is 2, which is even, hence the nodes are reversed. - The length of the third group is 3, which is odd, hence no reversal occurs. - The length of the last group is 4, which is even, hence the nodes are reversed.
Example 2:
Input: head = [1,1,0,6] Output: [1,0,1,6] Explanation: - The length of the first group is 1. No reversal occurs. - The length of the second group is 2. The nodes are reversed. - The length of the last group is 1. No reversal occurs.
Example 3:
Input: head = [1,1,0,6,5] Output: [1,0,1,5,6] Explanation: - The length of the first group is 1. No reversal occurs. - The length of the second group is 2. The nodes are reversed. - The length of the last group is 2. The nodes are reversed.
Constraints:
- The number of nodes in the list is in the range
[1, 105]
. 0 <= Node.val <= 105