2213. Longest Substring of One Repeating Character¶
Problem
You are given a 0-indexed string s
. You are also given a 0-indexed string queryCharacters
of length k
and a 0-indexed array of integer indices queryIndices
of length k
, both of which are used to describe k
queries.
The ith
query updates the character in s
at index queryIndices[i]
to the character queryCharacters[i]
.
Return an array lengths
of length k
where lengths[i]
is the length of the longest substring of s
consisting of only one repeating character after the ith
query is performed.
Example 1:
Input: s = "babacc", queryCharacters = "bcb", queryIndices = [1,3,3] Output: [3,3,4] Explanation: - 1st query updates s = "bbbacc". The longest substring consisting of one repeating character is "bbb" with length 3. - 2nd query updates s = "bbbccc". The longest substring consisting of one repeating character can be "bbb" or "ccc" with length 3. - 3rd query updates s = "bbbbcc". The longest substring consisting of one repeating character is "bbbb" with length 4. Thus, we return [3,3,4].
Example 2:
Input: s = "abyzz", queryCharacters = "aa", queryIndices = [2,1] Output: [2,3] Explanation: - 1st query updates s = "abazz". The longest substring consisting of one repeating character is "zz" with length 2. - 2nd query updates s = "aaazz". The longest substring consisting of one repeating character is "aaa" with length 3. Thus, we return [2,3].
Constraints:
1 <= s.length <= 105
s
consists of lowercase English letters.k == queryCharacters.length == queryIndices.length
1 <= k <= 105
queryCharacters
consists of lowercase English letters.0 <= queryIndices[i] < s.length