2612. Minimum Reverse Operations¶
Problem
You are given an integer n
and an integer p
in the range [0, n - 1]
. Representing a 0-indexed array arr
of length n
where all positions are set to 0
's, except position p
which is set to 1
.
You are also given an integer array banned
containing some positions from the array. For the ith position in banned
, arr[banned[i]] = 0
, and banned[i] != p
.
You can perform multiple operations on arr
. In an operation, you can choose a subarray with size k
and reverse the subarray. However, the 1
in arr
should never go to any of the positions in banned
. In other words, after each operation arr[banned[i]]
remains 0
.
Return an array ans
where for each i
from [0, n - 1]
, ans[i]
is the minimum number of reverse operations needed to bring the 1
to position i
in arr, or -1
if it is impossible.
- A subarray is a contiguous non-empty sequence of elements within an array.
- The values of
ans[i]
are independent for alli
's. - The reverse of an array is an array containing the values in reverse order.
Example 1:
Input: n = 4, p = 0, banned = [1,2], k = 4 Output: [0,-1,-1,1] Explanation: In this casek = 4
so there is only one possible reverse operation we can perform, which is reversing the whole array. Initially, 1 is placed at position 0 so the amount of operations we need for position 0 is0
. We can never place a 1 on the banned positions, so the answer for positions 1 and 2 is-1
. Finally, with one reverse operation we can bring the 1 to index 3, so the answer for position 3 is1
.
Example 2:
Input: n = 5, p = 0, banned = [2,4], k = 3 Output: [0,-1,-1,-1,-1] Explanation: In this case the 1 is initially at position 0, so the answer for that position is0
. We can perform reverse operations of size 3. The 1 is currently located at position 0, so we need to reverse the subarray[0, 2]
for it to leave that position, but reversing that subarray makes position 2 have a 1, which shouldn't happen. So, we can't move the 1 from position 0, making the result for all the other positions-1
.
Example 3:
Input: n = 4, p = 2, banned = [0,1,3], k = 1 Output: [-1,-1,0,-1] Explanation: In this case we can only perform reverse operations of size 1. So the 1 never changes its position.
Constraints:
1 <= n <= 105
0 <= p <= n - 1
0 <= banned.length <= n - 1
0 <= banned[i] <= n - 1
1 <= k <= n
banned[i] != p
- all values in
banned
are unique